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Chapter 08 · Unit 8 · 5 syllabus hours

Cosmochemistry

Chemistry beyond Earth: geological systems, the age of rocks and of the Earth, cosmic rays and their fingerprints in meteorites, comets, black holes, nuclear reactions in stars, and the solar neutrino hypothesis.

Semester VII CHEM7012 Nuclear Analytical 5 syllabus hours ≈ 20 min read book-built stars & dating
Unit 8 · Cosmochemistry Live

1 Chapter overview

Every atom of carbon in your body, every atom of iron in your blood, was forged by nuclear reactions outside the Earth. Cosmochemistry is the application of chemistry — above all, nuclear chemistry — to the cosmos: to the rocks of the Earth, to meteorites and comets, to cosmic rays, and to the stars themselves, where the elements are made.

A chemist has a special claim on this subject. The decay law N=N0e−λtN = N_0 e^{-\lambda t} that you used in Chapter 2 to count laboratory activities is the same law that dates a 4.5-billion-year-old meteorite. The fusion reactions that power the Sun are nuclear reactions with measurable cross-sections, branching ratios and Q-values. The "solar neutrino problem" was solved by particle physics, but it was posed by counting individual argon atoms produced by a neutrino capture reaction — analytical chemistry at its most extreme.

📌 Definition — Cosmochemistry

The study of the chemical and isotopic composition of the universe: the Earth and its reservoirs, meteorites, comets, cosmic rays, and the nuclear reactions in stars that synthesise the elements. For this paper it reduces to five examinable blocks: (i) geological systems, (ii) radiometric dating and the age of the Earth, (iii) cosmic rays and meteorites, (iv) comets and black holes, and (v) stellar nuclear reactions and the solar neutrino hypothesis.

Read this chapter as a story in one line: stars make the elements → meteorites preserve the recipe → cosmic rays leave fingerprints → radioactive clocks date the whole story → neutrinos let us look inside the Sun today. The derivations you must be able to reproduce are the radiometric age equation, the isochron equation, and the net energetics of the pp chain and the CNO cycle.

2 Core concepts

2.1 · Geological systems — Earth's reservoirs and geochemical cycles

The Earth is chemically differentiated into three great reservoirs:

  • Crust — the thin outer skin. Continental crust (~30–70 km thick, granitic, silica-rich "felsic" rocks) and oceanic crust (~5–10 km, basaltic, "mafic" rocks). It is where we sample rocks, and it is enriched in the heat-producing radioactive elements U, Th and K.
  • Mantle — from the base of the crust (the Mohorovičić discontinuity) down to ~2900 km; dominantly peridotite, i.e. magnesium–iron silicates (olivine, pyroxenes). Convection in the mantle drives plate tectonics.
  • Core — an iron–nickel alloy. The outer core (~2900–5150 km) is liquid and its motion generates the geomagnetic field; the inner core (~5150–6371 km) is solid despite enormous temperature, held so by pressure.

These reservoirs exchange matter through geochemical cycles: the rock cycle (igneous rocks weather to sediments → lithify to sedimentary rocks → bury and metamorphose → melt back to magma), the water cycle, and the carbon cycle. Plate tectonics — seafloor spreading at ridges and destruction of crust at subduction zones — is the great recycling engine. Why this matters for nuclear chemistry: magmatic differentiation fractionates parent and daughter elements differently (e.g. Rb follows K into evolved melts while Sr follows Ca into early crystals), and that fractionation is exactly what the isochron method exploits to date rocks (§3.2).

2.2 · The age of rocks — principles of radiometric dating

A radioactive parent P decays to a stable daughter D with decay constant λ\lambda, independent of temperature, pressure and chemical state — because decay is a nuclear process, while chemistry only rearranges electrons. If a mineral has remained a closed system since it formed (no parent or daughter entered or left except by decay), the daughter that has accumulated is a clock:

  • Assumptions: (i) the decay constant is known and invariant; (ii) the system stayed closed; (iii) the amount of daughter present initially is known or can be corrected for (the isochron method does this).
  • The age follows from the measured daughter-to-parent ratio — derived in §3.1.

The four workhorse clocks of geochronology:

SystemParent → daughtert1/2t_{1/2}Useful rangeTypical material
U–Pb238U→206Pb^{238}\mathrm{U} \rightarrow {}^{206}\mathrm{Pb}, 235U→207Pb^{235}\mathrm{U} \rightarrow {}^{207}\mathrm{Pb}4.47 Ga; 0.704 Ga~1 Ma – 4.5 GaZircon (excludes Pb at formation, retains U)
K–Ar40K→40Ar^{40}\mathrm{K} \rightarrow {}^{40}\mathrm{Ar} (electron capture, 10.7%)1.25 Ga~10 ka – 4.5 GaVolcanic rocks, micas, feldspars
Rb–Sr87Rb→87Sr^{87}\mathrm{Rb} \rightarrow {}^{87}\mathrm{Sr} (β−\beta^-)48.8 Ga~10 Ma – 4.5 GaMicas, feldspars, whole rocks (isochron)
14C^{14}\mathrm{C}14C→14N^{14}\mathrm{C} \rightarrow {}^{14}\mathrm{N} (β−\beta^-)5730 y~0.3 – 50 kaWood, charcoal, bone, shells
⚠️ Exam traps

(i) K–Ar dates the last cooling below the argon-retention temperature (~300 °C for micas) — reheating resets the clock because Ar escapes. (ii) ¹⁴C ages are reported by convention with the Libby half-life (5568 y), not the physical 5730 y. (iii) Rb–Sr needs the isochron because rocks always contain initial ⁸⁷Sr.

2.3 · The age of the Earth

Terrestrial rocks only give a lower limit: the oldest Earth materials are Jack Hills (Australia) zircons at ~4.4 Ga (U–Pb), but Earth's surface has been reworked by plate tectonics. The true age comes from meteorites, which sample undifferentiated solar-system material: in 1956 Patterson measured the Pb–Pb isochron of the Canyon Diablo iron meteorite and other meteorites and obtained 4.55 Ga — the accepted age of the Earth, quoted today as ≈ 4.54 Ga. Calcium-aluminium-rich inclusions (CAIs) in carbonaceous chondrites, the first solids to condense from the solar nebula, date to 4.567 Ga.

2.4 · Cosmic rays

Primary cosmic rays are high-energy charged particles arriving from space: ~89% protons, ~9% alpha particles and ~1–2% heavier nuclei (up to iron), with energies from ~10⁹ eV to beyond 10²⁰ eV. They are accelerated mainly in supernova remnants (Fermi shock acceleration); the lowest-energy flux is modulated by the solar wind.

Secondary cosmic rays are produced when primaries smash into atmospheric nuclei: air showers of pions (→ muons), neutrons, protons and electromagnetic cascades. Sea-level cosmic radiation is mostly muons.

  • Latitude effect: Earth's magnetic field deflects low-energy primaries most at the magnetic equator, so the flux is higher near the poles (and shows an east–west asymmetry, proving primaries are mostly positive).
  • Altitude effect: flux rises with altitude to the Pfotzer maximum (~15–20 km) and then falls — secondaries are absorbed as they descend.
  • Cosmogenic nuclides: secondary neutrons make radioactive nuclides in the atmosphere and in exposed rock — 14N(n,p)14C^{14}\mathrm{N}(n,p){}^{14}\mathrm{C}, and 10Be^{10}\mathrm{Be} (t1/2≈1.4t_{1/2} \approx 1.4 Ma), 36Cl^{36}\mathrm{Cl} (~0.30 Ma), 26Al^{26}\mathrm{Al} (~0.72 Ma) by spallation. These are tracers of solar activity, exposure ages and groundwater.

2.5 · Meteorites

Meteorites are fragments of asteroids (and a few of the Moon and Mars) that survive atmospheric entry. Classification:

  • Stones — chondrites: undifferentiated, containing chondrules (mm-sized once-molten droplets). Subdivided into ordinary, carbonaceous (volatile- and organic-rich; the CI chondrites match the solar photosphere element-for-element and define bulk solar-system composition) and enstatite chondrites.
  • Stones — achondrites: differentiated basalts from melted parent bodies (e.g. HED meteorites from the asteroid Vesta).
  • Irons: Fe–Ni alloys from the cores of disrupted planetesimals; show Widmanstätten patterns (kamacite/taenite intergrowths) proving cooling over millions of years.
  • Stony-irons (pallasites, mesosiderites): core–mantle boundary material.

What they tell us: (i) the age of the solar system — CAIs at 4.567 Ga, chondrules slightly younger; (ii) the initial isotopic composition of the solar nebula (e.g. initial ⁸⁷Sr/⁸⁶Sr ≈ 0.699, "BABI"); (iii) extinct radionuclides (²⁶Al, ⁶⁰Fe) whose daughter excesses date early processes; (iv) cosmic-ray exposure ages from cosmogenic nuclides, telling how long a meteoroid travelled in space.

2.6 · Comets

Comets are kilometre-sized icy planetesimals — "dirty snowballs" of water ice plus CO, CO₂, CH₄ and NH₃ ices mixed with silicate dust and organics. Far from the Sun they are inert nuclei; near the Sun, sublimation drives a coma and two tails (an ion tail pushed straight back by the solar wind, and a curved dust tail).

  • Kuiper belt (~30–50 AU beyond Neptune): source of short-period comets.
  • Oort cloud (~2,000–100,000 AU, nearly a light-year out): spherical reservoir, source of long-period comets (e.g. 1P/Halley, period 76 y, is technically a short-period/Kuiper-type example often quoted).

2.7 · Black holes

A black hole is a region where mass is so compact that the escape velocity exceeds the speed of light. Its characteristic size is the Schwarzschild radius rs=2GM/c2r_s = 2GM/c^2 (~3 km per solar mass). Formation: the iron core of a massive star (progenitor ≳ 20–25 M⊙M_\odot) collapses; if the remnant exceeds the Tolman–Oppenheimer–Volkoff limit (~2–3 M⊙M_\odot; white dwarfs are capped by the Chandrasekhar limit, 1.44 M⊙M_\odot), nothing halts the collapse.

  • Stellar-mass black holes (~3–10² M⊙M_\odot) — e.g. Cygnus X-1, detected via X-rays from an accretion disc fed by a companion star; now also via gravitational waves from mergers.
  • Supermassive black holes (10⁶–10¹⁰ M⊙M_\odot) — at the centres of galaxies, e.g. Sagittarius A* (~4×10⁶ M⊙M_\odot) in the Milky Way, M87* imaged by the Event Horizon Telescope.

2.8 · Nuclear reactions in stars — how the elements are made

Stars shine by fusion: light nuclei combine into heavier ones, releasing the mass difference as energy. Which reactions run depends on core temperature:

  • pp chain (Sun-like stars, core ~1.5×10⁷ K): protons fuse via p+p→d+e++νep + p \rightarrow d + e^+ + \nu_e. Three branches — pp I (~86% in the Sun), pp II (~14%, via ⁷Be) and pp III (~0.02%, via ⁸B, source of the high-energy neutrinos Homestake saw).
  • CNO cycle (massive stars, T ≳ 1.8×10⁷ K): ¹²C catalyses the same net conversion 4p → ⁴He; strongly temperature-dependent, so it dominates in hot stars.
  • Triple-alpha process (He burning, T ~ 10⁸ K, red giants): 3 4He→12C+γ3\,^{4}\mathrm{He} \rightarrow {}^{12}\mathrm{C} + \gamma, through the Hoyle resonance state; followed by 12C(α,γ)16O^{12}\mathrm{C}(\alpha,\gamma){}^{16}\mathrm{O}.
  • Advanced burning (massive stars): carbon burning (~6×10⁸ K) → neon → oxygen burning (~1–2×10⁹ K) → silicon burning (~3×10⁹ K), ending at the iron peak (⁵⁶Ni → ⁵⁶Co → ⁵⁶Fe). Fusion beyond iron absorbs energy, so the core collapses and the star explodes as a supernova.
  • Heavy elements (beyond Fe) are built by neutron capture: the s-process (slow, in AGB stars during He-shell burning — neutron captures slower than β\beta decays, so the path hugs the valley of stability) and the r-process (rapid, in supernovae and neutron-star mergers — huge neutron fluxes drive nuclei far neutron-rich before they decay back). This s/r distinction (Burbidge–Burbidge–Fowler–Hoyle, 1957) is a favourite exam one-liner.
pp chainCNO cycle
Net reaction4 1H→4He+2e++2νe4\,^{1}\mathrm{H} \rightarrow {}^{4}\mathrm{He} + 2e^+ + 2\nu_e (Q = 26.73 MeV)
NeedsOnly protonsC, N, O as catalysts
DominatesT ≲ 1.8×10⁷ K (Sun)T ≳ 1.8×10⁷ K (massive stars)
Temperature sensitivity∝T4\propto T^4∝T17\propto T^{17} (approx.)

2.9 · The solar neutrino hypothesis (the solar neutrino problem)

If the Sun shines by the pp chain, it must emit ~10³⁸ electron-neutrinos per second. The standard solar model (Bahcall) predicts the flux at Earth; the Homestake experiment (Davis, 1968) tested it: 615 tonnes of perchloroethylene (C₂Cl₄) in a tank 1480 m underground in the Homestake gold mine, South Dakota, exploiting 37Cl(νe,e−)37Ar^{37}\mathrm{Cl}(\nu_e, e^-){}^{37}\mathrm{Ar} (threshold 0.814 MeV). Every few weeks the few dozen ³⁷Ar atoms produced were flushed out with helium and counted by their decay.

Result: ~2.6 SNU observed vs ~8 SNU predicted — about one-third. (1 SNU = 10⁻³⁶ captures per target atom per second.) Kamiokande (~1/2) and the gallium experiments GALLEX/SAGE (~1/2, sensitive to low-energy pp neutrinos) confirmed a deficit. For 30 years physicists argued whether the Sun or the neutrino was misunderstood.

Resolution: the Sudbury Neutrino Observatory (SNO, 2001) used heavy water to detect neutrinos three ways — charged-current (νₑ only), neutral-current (all flavours equally) and elastic scattering. The total flux matched the solar model; the νₑ flux was depleted because neutrinos change flavour (νₑ → ν_μ, ν_τ) en route, enhanced inside the Sun by the MSW effect. Neutrinos have mass and oscillate — Nobel Prize 2015 (Kajita, McDonald); Davis and Koshiba shared the 2002 prize for detecting the deficit. So the Sun was right all along, and the "problem" became a discovery.

3 Key derivations

3.1 · From the decay law to the radiometric age equation

🔍 Derivation — the age equation

Let PP be the number of parent atoms now and P0P_0 the number at formation (time tt ago). The decay law gives P=P0e−λtP = P_0 e^{-\lambda t}, i.e. P0=PeλtP_0 = P e^{\lambda t}. In a closed system every decayed parent becomes a daughter atom, so the radiogenic daughter now present is

D∗=P0−P=P (eλt−1)D^* = P_0 - P = P\,(e^{\lambda t} - 1)

Solving for tt:

(1)t=1λ ln⁡ ⁣(1+D∗P)t = \frac{1}{\lambda}\,\ln\!\left(1 + \frac{D^*}{P}\right)

with λ=ln⁡2/t1/2\lambda = \ln 2 / t_{1/2}. This is the master equation: measure the daughter/parent atom ratio, know the half-life, get the age. Two common variants: for branched decay (⁴⁰K → ⁴⁰Ar by electron capture with partial constant λAr\lambda_{\mathrm{Ar}}, the rest to ⁴⁰Ca), only the fraction λAr/λ\lambda_{\mathrm{Ar}}/\lambda of decays makes argon, giving t=1λ ln⁡ ⁣[1+λλAr40Ar∗40K]t = \frac{1}{\lambda}\,\ln\!\left[1 + \frac{\lambda}{\lambda_{\mathrm{Ar}}}\frac{{}^{40}\mathrm{Ar}^*}{{}^{40}\mathrm{K}}\right] and for ¹⁴C, where we measure activity A=A0e−λtA = A_0 e^{-\lambda t}, t=(1/λ)ln⁡(A0/A)t = (1/\lambda)\ln(A_0/A).

3.2 · The isochron equation (Rb–Sr)

🔍 Derivation — isochron

Rocks always contain some initial ⁸⁷Sr, so D∗D^* alone is unknown. Write the total ⁸⁷Sr now as initial plus radiogenic, then divide everything by the stable, non-radiogenic reference isotope ⁸⁶Sr (which never changes):

(87Sr86Sr)=(87Sr86Sr)0+(87Rb86Sr) ⁣(eλt−1)\left(\frac{{}^{87}\mathrm{Sr}}{{}^{86}\mathrm{Sr}}\right) = \left(\frac{{}^{87}\mathrm{Sr}}{{}^{86}\mathrm{Sr}}\right)_0 + \left(\frac{{}^{87}\mathrm{Rb}}{{}^{86}\mathrm{Sr}}\right)\!(e^{\lambda t} - 1)

Cogenetic samples (same age, same initial ratio, different Rb/Sr because minerals fractionate Rb and Sr differently) fall on a straight line of slope m=eλt−1m = e^{\lambda t} - 1:

(2)t=1λ ln⁡(1+m)(isochron age from slope m)t = \frac{1}{\lambda}\,\ln(1 + m)\qquad\text{(isochron age from slope }m\text{)}

The intercept gives the initial ⁸⁷Sr/⁸⁶Sr — itself precious (it fingerprints the source reservoir). The same construction gives the Pb–Pb isochron used for the age of the Earth: plotting ²⁰⁷Pb/²⁰⁴Pb vs ²⁰⁶Pb/²⁰⁴Pb for meteorites yields a line whose slope fixes t≈4.55t \approx 4.55 Ga with no need to measure uranium at all. Concordia (U–Pb): the parametric curve of ²⁰⁶Pb*/²³⁸U vs ²⁰⁷Pb*/²³⁵U as a function of age; samples that stayed closed plot on it (concordant); Pb loss displaces them along a discordia chord whose upper intercept still gives the crystallisation age.

3.3 · Net energetics of stellar burning

pp chain. The three branches all reduce to: four protons → one alpha particle. Two of the protons must become neutrons (p→n+e++νep \rightarrow n + e^+ + \nu_e), so the net reaction is

(3)4 1H⟶4He+2e++2νe,Q=26.73 MeV4\,^{1}\mathrm{H} \longrightarrow {}^{4}\mathrm{He} + 2e^+ + 2\nu_e,\qquad Q = 26.73\ \mathrm{MeV}

Energy check: mass of 4 × ¹H (4 × 1.007825 u) minus mass of ⁴He (4.002602 u) = 0.028697 u ≈ 26.73 MeV; the two positrons annihilate with ambient electrons (adding 2 × 1.022 MeV), while the two neutrinos carry away ~0.59 MeV each — escaping the Sun unseen and becoming the solar neutrino flux.

CNO cycle. The carbon–nitrogen–oxygen sequence 12C(p,γ)13N→13C(p,γ)14N(p,γ)15O→15N(p,α)12C^{12}\mathrm{C}(p,\gamma){}^{13}\mathrm{N} \rightarrow {}^{13}\mathrm{C}(p,\gamma){}^{14}\mathrm{N}(p,\gamma){}^{15}\mathrm{O} \rightarrow {}^{15}\mathrm{N}(p,\alpha){}^{12}\mathrm{C} consumes four protons and regenerates the ¹²C catalyst, giving exactly the same net reaction:

(4)4 1H→catalyst 12C4He+2e++2νe,Q=26.73 MeV4\,^{1}\mathrm{H} \xrightarrow[\text{catalyst } {}^{12}\mathrm{C}]{} {}^{4}\mathrm{He} + 2e^+ + 2\nu_e,\qquad Q = 26.73\ \mathrm{MeV}

Triple-alpha. In helium burning, two alphas form the unbound ⁸Be (lifetime ~10⁻¹⁶ s); before it falls apart a third alpha can strike it, resonating through the Hoyle state of ¹²C:

(5)3 4He⟶12C+γ,Q=7.27 MeV3\,^{4}\mathrm{He} \longrightarrow {}^{12}\mathrm{C} + \gamma,\qquad Q = 7.27\ \mathrm{MeV}

This step — impossible without the Hoyle resonance — is what makes carbon, and hence chemistry and life, possible at all.

4 Worked examples

Example 1 — K–Ar dating with branched decay. A volcanic sanidine crystal gives 40Ar∗/40K=0.0150^{40}\mathrm{Ar}^*/{}^{40}\mathrm{K} = 0.0150 (radiogenic argon only, corrected for atmospheric Ar). Find its age. t1/2(40K)=1.25t_{1/2}(^{40}\mathrm{K}) = 1.25 Ga; λAr=0.581×10−10 yr−1\lambda_{\mathrm{Ar}} = 0.581 \times 10^{-10}\ \mathrm{yr^{-1}}.

Total decay constant λ=ln⁡2/t1/2=0.6931/1.25×109=5.545×10−10 yr−1\lambda = \ln 2 / t_{1/2} = 0.6931 / 1.25 \times 10^9 = 5.545 \times 10^{-10}\ \mathrm{yr^{-1}}. Only the electron-capture branch makes argon, so use the branched age equation:

t=1λln⁡ ⁣[1+λλAr40Ar∗40K]t = \frac{1}{\lambda}\ln\!\left[1 + \frac{\lambda}{\lambda_{\mathrm{Ar}}}\frac{{}^{40}\mathrm{Ar}^*}{{}^{40}\mathrm{K}}\right]

λ/λAr=5.545/0.581=9.543\lambda/\lambda_{\mathrm{Ar}} = 5.545/0.581 = 9.543. Hence 1+9.543×0.0150=1.14311 + 9.543 \times 0.0150 = 1.1431, ln⁡(1.1431)=0.13374\ln(1.1431) = 0.13374, and

t=0.133745.545×10−10=2.41×108 yr≈241 Mat = \frac{0.13374}{5.545 \times 10^{-10}} = 2.41 \times 10^8\ \mathrm{yr} \approx 241\ \mathrm{Ma}

The crystal last cooled below its Ar-retention temperature ~241 million years ago. Note the naive unbranched formula would give only ~164 Ma — the branching correction matters.

Example 2 — U–Pb age. A zircon contains 206Pb∗/238U=0.600^{206}\mathrm{Pb}^*/{}^{238}\mathrm{U} = 0.600 (common-Pb corrected). Calculate its age. t1/2(238U)=4.468t_{1/2}(^{238}\mathrm{U}) = 4.468 Ga.

λ=ln⁡2/4.468×109=1.551×10−10 yr−1\lambda = \ln 2 / 4.468 \times 10^9 = 1.551 \times 10^{-10}\ \mathrm{yr^{-1}}. From Eq. (1):

t=11.551×10−10 ln⁡(1+0.600)=0.470001.551×10−10=3.03×109 yrt = \frac{1}{1.551 \times 10^{-10}}\,\ln(1 + 0.600) = \frac{0.47000}{1.551 \times 10^{-10}} = 3.03 \times 10^9\ \mathrm{yr}

≈ 3.03 Ga. In practice the ²⁰⁷Pb/²³⁵U clock is measured too, and the point is checked for concordance (both clocks agreeing) before the age is trusted.

Example 3 — Radiocarbon dating. A charcoal sample from an archaeological hearth shows one-quarter the ¹⁴C activity of living wood. How old is it? t1/2=5730t_{1/2} = 5730 y.

Activity follows A=A0e−λtA = A_0 e^{-\lambda t}, so t=(1/λ)ln⁡(A0/A)t = (1/\lambda)\ln(A_0/A) with λ=ln⁡2/5730=1.2097×10−4 yr−1\lambda = \ln 2/5730 = 1.2097 \times 10^{-4}\ \mathrm{yr^{-1}}:

t=ln⁡41.2097×10−4=1.386291.2097×10−4=11 460 yr≈11.5 kat = \frac{\ln 4}{1.2097 \times 10^{-4}} = \frac{1.38629}{1.2097 \times 10^{-4}} = 11\,460\ \mathrm{yr} \approx 11.5\ \mathrm{ka}

Exactly two half-lives, as expected for a factor of 4. (Reported radiocarbon ages use the Libby half-life, 5568 y, giving ~11.1 ka — always state the convention.)

Example 4 — Rb–Sr isochron age. Cogenetic minerals from a meteorite define an isochron of slope m=0.0700m = 0.0700. Find the age. λ(87Rb)=1.42×10−11 yr−1\lambda(^{87}\mathrm{Rb}) = 1.42 \times 10^{-11}\ \mathrm{yr^{-1}}.

From Eq. (2), t=(1/λ)ln⁡(1+m)t = (1/\lambda)\ln(1+m):

t=ln⁡(1.0700)1.42×10−11=0.0676591.42×10−11=4.76×109 yr≈4.76 Gat = \frac{\ln(1.0700)}{1.42 \times 10^{-11}} = \frac{0.067659}{1.42 \times 10^{-11}} = 4.76 \times 10^9\ \mathrm{yr} \approx 4.76\ \mathrm{Ga}

A primordial age — older than any Earth rock, consistent with meteoritic material that has been a closed system since the solar system formed. The intercept of the same isochron gives the solar system's initial ⁸⁷Sr/⁸⁶Sr ≈ 0.699.

Example 5 — Solar neutrino flux (order of magnitude). The Sun's luminosity is L=3.828×1026L = 3.828 \times 10^{26} W. Each pp-chain net reaction (Eq. 3) releases 26.73 MeV and 2 electron-neutrinos. Estimate (a) the neutrino production rate, (b) the flux at Earth (1 AU = 1.496×10111.496 \times 10^{11} m).

Energy per reaction: 26.73 MeV=26.73×1.602×10−13=4.282×10−12 J26.73\ \mathrm{MeV} = 26.73 \times 1.602 \times 10^{-13} = 4.282 \times 10^{-12}\ \mathrm{J}. Reactions per second = L/E=3.828×1026/4.282×10−12=8.94×1037 s−1L/E = 3.828 \times 10^{26} / 4.282 \times 10^{-12} = 8.94 \times 10^{37}\ \mathrm{s^{-1}}; with 2 νe\nu_e each:

Nν≈1.8×1038 s−1N_{\nu} \approx 1.8 \times 10^{38}\ \mathrm{s^{-1}}
Φ=Nν4πr2=1.79×10384π(1.496×1011)2≈6.4×1010 cm−2 s−1\Phi = \frac{N_{\nu}}{4\pi r^2} = \frac{1.79 \times 10^{38}}{4\pi(1.496 \times 10^{11})^2} \approx 6.4 \times 10^{10}\ \mathrm{cm^{-2}\,s^{-1}}

About sixty billion solar neutrinos pass through every square centimetre of you each second — and essentially none interact. This is the flux the Homestake experiment sampled a few atoms at a time.

5 Figures

Stellar nucleosynthesis flowchart Hydrogen burning by the pp chain or CNO cycle makes helium; helium burning by the triple-alpha process makes carbon and oxygen; carbon, oxygen and silicon burning in massive stars build up to the iron peak; the s-process in AGB stars and the r-process in supernovae make elements heavier than iron. Temperature thresholds rise at each stage. pp chain · 4p → ⁴He T ≳ 4×10⁶ K · Sun's core 1.5×10⁷ K CNO cycle (¹²C catalyst) T ≳ 1.8×10⁷ K · massive stars same net: +26.73 MeV He burning · triple-alpha 3 ⁴He → ¹²C + γ · T ~ 10⁸ K · red giants C burning → Ne, Na, Mg T ~ 6×10⁸ K · massive stars O burning → Si, S, Ar, Ca T ~ 1–2×10⁹ K Si burning → iron peak T ~ 3×10⁹ K · ends at ⁵⁶Fe (fusion stops) Core collapse → supernova fusion beyond Fe absorbs energy s-process slow n-capture · AGB stars r-process rapid n-capture · mergers Legend burning stage n-capture (A > Fe)
Fig. 8.1 — Stellar nucleosynthesis: rising core temperature unlocks heavier burning stages; neutron-capture (s- and r-processes) builds elements beyond iron.
Rb–Sr isochron diagram A plot of 87Sr/86Sr against 87Rb/86Sr for cogenetic minerals. The points fall on a straight line whose slope m equals e to the power lambda t minus 1, giving the age, and whose intercept gives the initial 87Sr/86Sr ratio. 0 1 2 3 0.70 0.75 0.80 0.85 ⁸⁷Rb / ⁸⁶Sr ⁸⁷Sr / ⁸⁶Sr intercept = initial ⁸⁷Sr/⁸⁶Sr slope m = e^(λt) − 1 → age Legend cogenetic minerals isochron, age t
Fig. 8.2 — The isochron: minerals of the same age but different Rb/Sr lie on a line whose slope gives the age and whose intercept gives the initial daughter ratio.
The solar neutrino experiment concept Electron neutrinos produced by fusion in the Sun's core travel to Earth. The Homestake experiment detected them in an underground tank via chlorine-37 capturing a neutrino to make argon-37, but counted only about one third of the predicted flux. SNO showed the missing neutrinos had changed flavour. Sun pp chain → νₑ νₑ νₑ νₑ ν_μ ν_τ flavour change en route (SNO, 2001) Earth Homestake tank 615 t C₂Cl₄ 1480 m underground ³⁷Cl(νₑ,e⁻)³⁷Ar count the ³⁷Ar atoms observed ≈ ⅓ of predicted Legend neutrino flight path
Fig. 8.3 — The solar neutrino experiment concept: Davis counted ³⁷Ar atoms made by neutrino capture deep underground; the one-third deficit was resolved when SNO showed neutrinos change flavour in flight.

6 PYQ bank

⚠️ Honest empty state — no PYQs on record

No question from Cosmochemistry (Unit 8) appeared in any of the five analysed papers (2020–2024). The PYQ bank for this chapter is therefore empty — not a single question on the age of rocks, cosmic rays, meteorites, stellar nuclear reactions or solar neutrinos was asked in those years. This chapter is book-built from the reference shelf (Faure; Clayton; Friedlander–Kennedy–Macias). The questions below are likely exam questions written for practice — they are NOT previous-year questions.

Practice Q1 (not a PYQ). Derive the radiometric age equation t=(1/λ)ln⁡(1+D∗/P)t = (1/\lambda)\ln(1 + D^*/P) starting from the radioactive decay law. State all assumptions.

From P=P0e−λtP = P_0 e^{-\lambda t}, P0=PeλtP_0 = Pe^{\lambda t}. In a closed system the radiogenic daughter is D∗=P0−P=P(eλt−1)D^* = P_0 - P = P(e^{\lambda t}-1), so eλt=1+D∗/Pe^{\lambda t} = 1 + D^*/P and t=(1/λ)ln⁡(1+D∗/P)t = (1/\lambda)\ln(1+D^*/P). Assumptions: (i) λ\lambda known and constant (nuclear process, unaffected by T/P/chemistry); (ii) closed system — no parent/daughter gained or lost except by decay; (iii) initial daughter D0D_0 known or corrected (isochron). (Worked in §3.1.)

Practice Q2 (not a PYQ). A meteorite isochron has slope 0.0700 for the Rb–Sr system (λ=1.42×10−11 yr−1\lambda = 1.42 \times 10^{-11}\ \mathrm{yr^{-1}}). Calculate its age and explain what the intercept means.

t=ln⁡(1.0700)/1.42×10−11=4.76×109t = \ln(1.0700)/1.42 \times 10^{-11} = 4.76 \times 10^9 yr ≈ 4.76 Ga. The intercept is the initial ⁸⁷Sr/⁸⁶Sr ratio (~0.699, BABI) — the isotopic composition of the solar nebula, a fingerprint of the source reservoir. (Worked in §4, Example 4.)

Practice Q3 (not a PYQ). Write the net reaction and energy release of the proton–proton chain. Why does the CNO cycle give the same net result?

4 1H→4He+2e++2νe4\,^{1}\mathrm{H} \rightarrow {}^{4}\mathrm{He} + 2e^+ + 2\nu_e, Q = 26.73 MeV. The CNO cycle consumes four protons and regenerates its ¹²C catalyst — carbon, nitrogen and oxygen are catalysts, not net reactants — so its net stoichiometry is identical, releasing the same 26.73 MeV per helium nucleus formed.

Practice Q4 (not a PYQ). Describe the Homestake solar neutrino experiment and state how the solar neutrino problem was resolved.

Davis (1968): 615 t of C₂Cl₄, 1480 m underground in the Homestake mine; reaction 37Cl(νe,e−)37Ar^{37}\mathrm{Cl}(\nu_e,e^-){}^{37}\mathrm{Ar}; the few dozen ³⁷Ar atoms produced were flushed out and counted. Observed ~2.6 SNU vs ~8 SNU predicted (~one-third). Resolution (SNO, 2001): heavy-water detector measured the total neutrino flux (neutral current, all flavours) — it matched the solar model — while the νₑ flux was depleted: neutrinos change flavour (νₑ → ν_μ, ν_τ) via the MSW effect. Nobel Prizes 2002 (Davis, Koshiba) and 2015 (Kajita, McDonald).

Practice Q5 (not a PYQ). Distinguish the s-process from the r-process in heavy-element nucleosynthesis.

s-process (slow): neutron captures slower than β\beta decays — operates in AGB stars during He-shell burning; the capture path hugs the valley of stability. r-process (rapid): neutron captures faster than decays — needs huge neutron fluxes in supernovae / neutron-star mergers; builds very neutron-rich nuclei that decay back to stability afterwards. (Burbidge–Burbidge–Fowler–Hoyle, 1957.)

7 Exam Q&A

Q1. Why is the radioactive decay constant unaffected by temperature, pressure or chemical combination?

Decay is a nuclear process governed by the weak/strong interactions inside the nucleus; temperature, pressure and chemistry only perturb the electron cloud (energies of eV), while nuclear transitions involve MeV — a million-fold mismatch. Hence λ\lambda is an immutable clock.

Q2. What is the currently accepted age of the Earth, and on what evidence does it rest?

≈ 4.54 Ga, from Patterson's (1956) Pb–Pb isochron of meteorites (Canyon Diablo troilite et al.), giving 4.55 Ga. Terrestrial rocks only give a lower limit (oldest: ~4.4 Ga Jack Hills zircons) because plate tectonics reworks the crust.

Q3. Distinguish primary and secondary cosmic rays.

Primary: high-energy particles arriving from space — ~89% protons, ~9% alphas, ~1–2% heavier nuclei, GeV to 10²⁰ eV, accelerated mainly in supernova remnants. Secondary: particles made when primaries hit air nuclei — pions → muons, neutrons, EM cascades; sea-level flux is mostly muons.

Q4. What are chondrites, and why are CI carbonaceous chondrites special?

Chondrites are undifferentiated stony meteorites containing chondrules — the most primitive solar-system solids. CI chondrites match the solar photosphere element-for-element (except volatiles), so they define the bulk composition of the solar system — the cosmochemical abundance standard.

Q5. Name the two reservoirs of comets and the comets each supplies.

Kuiper belt (~30–50 AU) → short-period comets; Oort cloud (~2,000–100,000 AU, spherical) → long-period comets. Comets are dirty snowballs: H₂O, CO₂, CO, CH₄, NH₃ ices + silicate dust + organics.

Q6. Write the Schwarzschild radius and state the two classes of black holes with one example each.

rs=2GM/c2r_s = 2GM/c^2 (≈ 3 km per solar mass). Stellar-mass (~3–10² M⊙M_\odot, e.g. Cygnus X-1, from core collapse of massive stars) and supermassive (10⁶–10¹⁰ M⊙M_\odot, e.g. Sagittarius A*, ~4×10⁶ M⊙M_\odot, at galactic centres).

Q7. Why does stellar fusion stop at iron?

Iron-peak nuclei (⁵⁶Fe) have the maximum binding energy per nucleon; fusing heavier nuclei would absorb energy instead of releasing it. With no radiation pressure to support it, the core collapses → supernova; elements beyond Fe are made by neutron capture (s- and r-processes), not fusion.

Q8. What is 1 SNU, and what did Homestake measure in these units?

1 SNU = 10⁻³⁶ captures per target atom per second. Homestake measured ~2.6 SNU against ~8 SNU predicted by the standard solar model — roughly one-third, the original solar neutrino problem.

8 Quick revision

Boxed results — the whole chapter on one screen

  • (1) Age equation: t=1λln⁡ ⁣(1+D∗/P)t = \frac{1}{\lambda}\ln\!\left(1 + D^*/P\right), λ=ln⁡2/t1/2\lambda = \ln 2/t_{1/2} — closed system, known initial daughter.
  • (2) Isochron age: t=1λln⁡(1+m)t = \frac{1}{\lambda}\ln(1+m), slope m=eλt−1m = e^{\lambda t}-1; intercept = initial daughter ratio.
  • (3) pp chain net: 4 1H→4He+2e++2νe4\,^{1}\mathrm{H} \rightarrow {}^{4}\mathrm{He} + 2e^+ + 2\nu_e, Q = 26.73 MeV.
  • (4) CNO net: identical net reaction, same 26.73 MeV; ¹²C is a catalyst; dominates at T ≳ 1.8×10⁷ K.
  • (5) Triple-alpha: 3 4He→12C+γ3\,^{4}\mathrm{He} \rightarrow {}^{12}\mathrm{C} + \gamma, Q = 7.27 MeV, T ~ 10⁸ K, Hoyle resonance.
  • Earth's age: ≈ 4.54 Ga (Patterson 1956, meteorite Pb–Pb isochron); CAIs 4.567 Ga; oldest Earth zircon ~4.4 Ga.
  • Homestake: ³⁷Cl(νₑ,e⁻)³⁷Ar, ~2.6 vs ~8 SNU (≈ ⅓); resolved by SNO (2001) — neutrino flavour change (MSW).
  • s vs r: slow n-capture in AGB stars vs rapid n-capture in supernovae/mergers (B²FH 1957).

Clock data

Systemt1/2t_{1/2}λ (yr−1)\lambda\ (\mathrm{yr^{-1}})Range
²³⁸U → ²⁰⁶Pb4.47 Ga1.55×10−101.55 \times 10^{-10}~1 Ma – 4.5 Ga
²³⁵U → ²⁰⁷Pb0.704 Ga9.85×10−109.85 \times 10^{-10}concordia pair
⁴⁰K → ⁴⁰Ar1.25 Ga5.55×10−105.55 \times 10^{-10} (total)~10 ka – 4.5 Ga
⁸⁷Rb → ⁸⁷Sr48.8 Ga1.42×10−111.42 \times 10^{-11}~10 Ma – 4.5 Ga
¹⁴C → ¹⁴N5730 y1.21×10−41.21 \times 10^{-4}~0.3 – 50 ka

Symbols

SymbolMeaning
P, D∗, D0P,\ D^*,\ D_0Parent now; radiogenic daughter; initial daughter
mmIsochron slope, m=eλt−1m = e^{\lambda t}-1
rsr_sSchwarzschild radius, rs=2GM/c2r_s = 2GM/c^2
SNUSolar neutrino unit = 10⁻³⁶ captures·atom⁻¹·s⁻¹
CAICalcium-aluminium-rich inclusion — first solar-system solids (4.567 Ga)
SSMStandard solar model (Bahcall) — predicted neutrino fluxes
MSWMikheyev–Smirnov–Wolfenstein effect — flavour conversion enhanced in matter